A wire of resistance 20 ohm having length 2m if length will be taken 3 times what will be new resistance?
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R=resistivity(rho)*length(l)/A(area of cross sec)
R=20 ohm initially at length l and area of cross sec A
rho is constant since it dosent depends on dimension
hence R∝l/A
new resistance R' when length is increased by 3 times
concept: when u increase length by 3 times area of cross sec will decreases by 3 times
R'=3l/(A/3)
R'=6l/A
R'=6R
hence resistance increases by 6 times
new resistance= 6*20=120 ohms
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