Question

A wire of resistance 20 ohm is bent in the form of a closed square

Answer 1

then what is your question man........

Answer 2

On bending 20 ohms resistance into the square. At the ends of the vertexes/diagonal, these two points will divide the resistance into 2 equal resistances 10 ohms each. These are the now in the parallel order. The total/final resistance will be 5 ohms. 1/R=1+R1/1+R/2

= 1/10+1/10

= 2/10 ohms, R=5 ohms