Question

a wire of resistance 20 ohm is bent in the form of closed circle.What is the affective resistance between 2 points at the end of any diameter of the circle. pls explain by figure..... It's urgent.....​

Answer 1

Step-by-step explanation:

Resistance given here is 20 ohm

As it is bend into wire so, L = 2πr

so, Ri = Rho×2πr/A = 20 ohm

Now, resistance between two point at the end of diameter can be given by

1/R = (1/Ri/2)+(1/Ri/2) {as half of the wire is attached to the other half so it may be considered as parallel connection}

1/R = 1/10+1/10 { Ri = 20ohm so Ri/2 = 10 ohm }

or 1/R = 2/10

so, R = 5 ohm ,(across ends of diameter)

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