a wire of resistance 20 ohm is bent to form a closed square what is the resistance across a diagonal of the square
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If the wire is bent to form a square,then the resistance of the side of the square=20/4=5
Across the diagonal,
first calculate the resistance through the two sides that is
R1=5+5=10
then through the diagonal,R2=root over of(5^2+5^2)=5√2
as R1 and R2 are parallel to each other,
1/R=1/R1+1/R2
1/R=1/10+1/5*√2
1/R=( √2 +)/10* √2
1/R=2* √2 /10* √2
√2 cancelled in both,hence
1/R=2/10
1/R=1/5
R=5
Hope it helped you.
Across the diagonal,
first calculate the resistance through the two sides that is
R1=5+5=10
then through the diagonal,R2=root over of(5^2+5^2)=5√2
as R1 and R2 are parallel to each other,
1/R=1/R1+1/R2
1/R=1/10+1/5*√2
1/R=( √2 +)/10* √2
1/R=2* √2 /10* √2
√2 cancelled in both,hence
1/R=2/10
1/R=1/5
R=5
Hope it helped you.
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