A wire of resistance 20 ohm is tripled on it. Find the new resistance
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Answer:
L
1
A 1
=L 2
A 2
[∵ V is constant]
⇒L
1×A 1
=2L 1
A 2
A 2
A 1= 12
R 2
R 1
=(
L 2L 1
( A 1
A 2)R 2
R 1
= 21 × 21
⇒R 2
=4×20
=80Ω
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