Question

A wire of resistance 20 ohm is tripled on it. Find the new resistance​

Answer 1

Answer:

L

1

A 1

=L 2

A 2

[∵ V is constant]

⇒L

1×A 1

=2L 1

A 2

A 2

A 1= 12

R 2

R 1

=(

L 2L 1

( A 1

A 2)R 2

R 1

= 21 × 21

⇒R 2

=4×20

=80Ω