Question

a wire of resistance 20ohm is drawn in the form of a square. find net resistance across its one side and diagonal​

Answer 1

Answer:

Net resistance across one side is 3.75 Ohms.

Net resistance across diagonal is 5 Ohms.

Explanation:

check attached image.

Answer 2

Answer:

Across one side Net resistance would be 3.75ohm

Across Diagonal Net resistance Would be 5ohm

Explanation:

In this Question,

We have been given that

A wire of 20ohm is drawn in the form of square

We need to find the net resistance across its one side and diagonal.

Across one side

5ohm will be parallel to 15 ohm

Applying the formula we get

$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$

Here, $R_{1}=5\ and\ R_{2}=15$

Putting the values we get,

$\frac{1}{R}=\frac{1}{5}+\frac{1}{15}$

$\frac{1}{R}=\frac{3+1}{15}$

$\frac{1}{R}=\frac{4}{15}$

$R=\frac{15}{4}$

R=3.75ohm

Similarly for Diagonal

10ohm will be parallel to 10ohm

$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$

Here, $R_{1}=10\ and\ R_{2}=10$

$\frac{1}{R}=\frac{1}{10}+\frac{1}{10}$

$\frac{1}{R}=\frac{2}{10}$

R=10ohm

Net resistance across its one side is 3.75ohm

Net resistance across its diagonal is 10ohm