Question

a wire of resistance 20ohmis bent to form a closed square.what is the resistance across a diagonal of square?​

Answer 1

Explanation:

If the wire is bent to form a square, then the resistance of the side of the square =420=5Ω

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ω

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ωthen through the diagonal,

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ωthen through the diagonal,R2=(52+52)=5×2

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ωthen through the diagonal,R2=(52+52)=5×2As R1 and R2 are paralell to each other

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ωthen through the diagonal,R2=(52+52)=5×2As R1 and R2 are paralell to each otherR1=R11+R21

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ωthen through the diagonal,R2=(52+52)=5×2As R1 and R2 are paralell to each otherR1=R11+R21R1=101+5×21

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ωthen through the diagonal,R2=(52+52)=5×2As R1 and R2 are paralell to each otherR1=R11+R21R1=101+5×21R1=10×2(2+2)

the wire is bent to form a square, then the resistance of the side of the square =420=5ΩAcross the diagonal, first calculate resistance through the two sides i.e. R1=5+5=10Ωthen through the diagonal,R2=(52+52)=5×2As R1 and R2 are paralell to each otherR1=R11+R21R1=101+5×21R1=10×2(2+2)R1=10×2

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