A wire of resistance 24 ohm bent to a close a square . What is the resistance across a diagonal of the sqaure
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Answer:
6√2 is the resistance of the diagonal.
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Answer:
There will be two series combination of two sides of sqaure on each side of diagonal. Now, Resistance of series combination = 6 + 6 = 12 ohm. This 12 ohm is on both sides of the diagonal. ... Hence, the net resistance of the wire in square form is 6 ohm.
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