A wire of resistance 25 ohm is pulled to four times its length. Calculate the new resistance.
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Answer:
Step-by-step explanation:
Given resistance=R1=25ohm
Lett the length of the wire be=L
Therefore the new length of the wire=2L
Since, when the length is doubled, cross sectional area becomes half.
Therefore new resistance=R=2L/(A/2)=4L/A
R=4 multiplied by 25= 100
R=100
The new resistance = 100
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