a wire of resistance 3 ohm and lenght 10 cm is stretched to lenght 30 cm .assuming that it has a uniform cross section,what will be the new resistance
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Original Resistance, R = ρ × l/A
The resistance of the conductor is directly proportional to its length and inversely proportional to its cross sectional area.
The wire is tripled of its previous length so the resistance will be 3l
The new cross sectional area will be A/3
Rnew = 3 × ρ × l/ A/3
= 9R ( R = ρ × l/A)
= 9 × 3
= 27 Ω
HOPE IT HELPS ^_^
Original Resistance, R = ρ × l/A
The resistance of the conductor is directly proportional to its length and inversely proportional to its cross sectional area.
The wire is tripled of its previous length so the resistance will be 3l
The new cross sectional area will be A/3
Rnew = 3 × ρ × l/ A/3
= 9R ( R = ρ × l/A)
= 9 × 3
= 27 Ω
HOPE IT HELPS ^_^
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