A wire of resistance 32Ω is doubled on it and this
process is repeated once again. Find the new
resistance of the wire.
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1
Answer:
As length of the wire is reduced to L/2, area increases by 2 times. Again the process is repeated, hence L will become L/4As length of the wire reduced by L/4, area increases by 4 times. The new resistance of the wire will be effective resistance of the resistors in parallel.
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2
Answer:
We know,R is directly proportional to length of the wire L,and inversely proportional to the area of cross section of the wire A. (i)When length is doubled,thr original resistance R becomes 2R,i.e.,the resistance also doubles. ... Hence new resistance becomes 1/4th of original R;since R is inversely related to the area A.
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