Question

A wire of resistance 4.5 Q and
length 150 cm, has an area of
cross-section of 0.04 cm^-2.
Calculate sp. resistance of the
wire. *​

Answer 1

Answer:

∴ Sp. Resistance of wire P = Ra/1

P = (4.5 × 0.04)/150 = 180/150000 = 0.0012 Ω – cm

R = 4.5 Ω, l = 150 cm, a = 0.04 cm2 a2 = a/3

Answer 2

Answer:

1.2×10-³ ohm.m

Explanation:

resistance of the wire= 4.5ohm

length =150 cm = 1.5m

area of cross section= 0.04 cm²= 0.0004m²= 4×10-⁴m

specific resistance= (r×a)/l

= (4.5×4×10-4)/1.5 ohm.m

=(18×10-⁴)/1.5ohm.m

12×10-⁴ ohm.m

1.2×10-³ ohm.m