A wire of resistance 4ohm is bent into a
circle. The resistance between the ends of a diameter of the circle is ? can some one please solve it
Answers
Answered by
1
Answer:
Explanation:
Given :
Resistance =R=4ohms
Let diameter of circle be AB.
The resistance of upper part will be 2R and lower part of circle will be 2R
The resistance will be in parallel.
R1=R2=2R
1/Rp=1/R1+1/R2
=1/2R+1/2R
=2/2R
1/Rp=1/R
∴Rp=R ohms
∴ Resistance between two diametrically opposite ends is R ohms
Answered by
1
Answer:
R
Explanation:
eff resistance=R1.R2/R1+R2
=2R.2R/2R+2R
=4R^2/4R=R
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