A wire of resistance 5 Ω is divided into five equal parts. These parts are
connected in parallel. Find the new resistance.
Answers
Answered by
1
On dividing, l -> l/5 (for each wire)
Resistance of each wire = 5/5 = 1 ohm
On connecting in parallel,
1/R = 1/1 + 1/1 + 1/1 + 1/1 + 1/1 = 5
R = 1/5 = 0.2 ohm
Answered by
0
Answer: 5Ω
Explanation:
the resistance of wire of 5Ω is divide into 5 thus , resistance of one part is 1Ω , if they are connected in parallel ,
the total resistance = 1/5 + 1/5 + 1/5 + 1/5 + 1/5 + 1/5 / 5 = 25/5 = 5 [ L.C.M = 5 ]
(OR)
the total resistance connected in parallel series = n/R
= 5/25
= 1/5
∴ R = 5 Ω
Similar questions