Question

A wire of resistance 5Ω is uniformly stretched until its new length becomes 4 times the original length.find its new resistance​

Answer 1

Explanation:

R1/R2=(L1/L2)^2

5/R2=(1/4)^2

R2=16×5

R2=80ohm

Answer 2

Answer:

Here's your answer

Explanation:

V= A'l'=Al

A'/A=l/4l (because l'=4l)

A'/A= 1/4

R'/R= l'A'/A/l

R'/5=4×4

R' = 16× 5 = 80 ohm

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