A wire of resistance 5 ohm is bent in the form of a closed circle find the resistance between two points at the ends of any diameter of the circle
Answers
Answered by
6
Answer:
Explanation:
Resistance of each half circle will be 2.5 ohm.
The end points are in parallel
(1/R) = (1/2.5) +(1/2.5)
=2/2.5
=R = 2.5/2
=R= 1.25 ohm
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Answered by
2
Answer:
1.25Ω
Explanation:
The diametrically opposite points divides the resistance into half of the total resistance.
Resistance of each semi circle R1 = R2
= 5/2=2.5Ω
These resistance are connected in parallel
So, equivalent resistance Req = R1R2/R1+R2 =
2.5×2.5/2.5+2.5 = 1.25Ω
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