A wire of resistance 5 ohm is drawn out so that its length is increased to twice its original length. Calculate its new resistance
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Explanation:
we have R=
A
ρL
if we increase the length the resistance is also increase
In this case length become 2L so R
1
=
A
ρ2L
=2R
R=5Ω
⇒R
1
=2×5=10Ω
new resistance is 10Ω ,resistivity is constant it is a matrial property
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