Question

A wire of resistance 5 ohm is drawn out so that its length is increased to twice its original length. Calculate its new resistance ​

Answer 1

Explanation:

we have R=

A

ρL

if we increase the length the resistance is also increase

In this case length become 2L so R

1

=

A

ρ2L

=2R

R=5Ω

⇒R

1

=2×5=10Ω

new resistance is 10Ω ,resistivity is constant it is a matrial property