Question

a wire of resistance 5 ohm is stretched till its radius gets halved .It is then cut into teo parts with their length in the ratio 1:3 .The two parts are connected in parallel across a battery of emf 6V and negligible internal resistance.Find the current suplied by the battery​

Answer 1

Answer:

When the wire is stretched its Volume remains the same. When the resistance of wire R=60Ω is cut into two equal parts, the length becomes half but area remains the same. Hence resistance of each part is R1= R/2 = 60/2 = 30Ω..