A wire of resistance 50 ohm is stretched twice its length. What will be its new resistance ?
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ohm law can be used
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R = 50Ω
L = L
A = A
L' = 2L
volume of initial and final wire
s are equal so
A×L = A'×L'
A' = A×L/2L
A' = A/2
R' = resistivity×L/A = 4R
[' means final]
please mark it as the brainliest answer
L = L
A = A
L' = 2L
volume of initial and final wire
s are equal so
A×L = A'×L'
A' = A×L/2L
A' = A/2
R' = resistivity×L/A = 4R
[' means final]
please mark it as the brainliest answer
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