A wire of resistance 5ohm is bent to form a square.What is the equivalent resistance in ohm across the diagonally opposite vertices of the square?
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WHEN IT WILL BENDED TO FORM SQUARE
SO, THE LENGTH WILL BECOME HALF
THERE FORE THE RESISTANCE WILL ALSO BECOME HALF .
THE 2 WIRES FROM OPPOSITE VERTICES WILL BE IN PARALLEL.
SO, 1/R = 1/5 +1/5
1/R = 2/5
R = 2.5 ohm
SO, THE LENGTH WILL BECOME HALF
THERE FORE THE RESISTANCE WILL ALSO BECOME HALF .
THE 2 WIRES FROM OPPOSITE VERTICES WILL BE IN PARALLEL.
SO, 1/R = 1/5 +1/5
1/R = 2/5
R = 2.5 ohm
mishrameera316:
Can u give me the solution pic
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1
Is the answer 1.25ohm
Since all around the sides there will be 1.25 ohm so, accross the diagonals 2.5 ohm will be in parallel. So the ans must be 1.25 ohm
Since all around the sides there will be 1.25 ohm so, accross the diagonals 2.5 ohm will be in parallel. So the ans must be 1.25 ohm
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