Question

A wire of resistance 8 ohm having length 20 cm is doubled on itself. What is the new resistance?

Answer 1

Answer:

R2 = R/4 ohm

Explanation:

R = ρl/A

Initially, R1 = R, l1 = l, A1 = A

On doubling on itself, the length is reduced to half and the area of cross- section is doubled.

Now, R2 =?, l2 = l/2, A2 = 2A

R1/R2 = l1/l2 x A2/A1

= 2 x 2 = 4

so, R2 = R1/4 = R/4 ohm

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