Question

a wire of resistance 8 ohm having length 20 cm is tripled on itself . what is its new new resistance?

Answer 1

Answer:

para nshi vvjjmkkliiiiiiii

Answer 2

Resistance = 8 Ω

Length, l = 20 cm

We know,

$\sf{R=\rho \dfrac{l}{a} }\\\\\sf{\hookrightarrow R=\rho \dfrac{20}{a} }$

A/q,

Length is tripled, i.e. 20 × 3 = 60 cm

Now,

$\sf{R'=\rho \dfrac{l}{a} }\\\\\sf{\hookrightarrow R'=\rho \dfrac{60}{a} }\\\\\sf{\hookrightarrow R'=3 \times \rho\dfrac{20}{a} }\\\\\sf{\hookrightarrow R'=3R}$

$\sf{\hookrightarrow R'=24\ \Omega}$

Hence, the new resistance is 24 Ω.