Physics, asked by vimalpandharpure11, 7 months ago

a wire of resistance 80 ohm is cut into 8 equal pieces. these pieces are joined in parallel. find the net resistance of its combination
.


Plzzz answer fast​

Answers

Answered by rohitprajapat099
0

Answer:

0.8 ohm.

this is the answer.......

Answered by zunerakhaleel
0

Answer:

The correct answer is 8.89 ohm.

Explanation:

The expression for the equivalent resistance in the parallel combination is as follows;

\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}

R

1

=

R

1

1

+

R

2

1

+

R

3

1

Here, R{1},R_{2},R_{3}R1,R

2

,R

3

are the resistances.

It is given in the problem that a wire whose resistance is 80 ohm is cut into three pieces of equal length.

The value of each resistance is equal to \frac{80}{3}

3

80

.

Put R{1}=R_{2}=R_{3}=\frac{80}{3}R1=R

2

=R

3

=

3

80

.

\frac{1}{R}=\frac{3}{80}+\frac{3}{80}+\frac{3}{80}

R

1

=

80

3

+

80

3

+

80

3

R=\frac{80}{9}R=

9

80

R=8.89 ohmR=8.89ohm

Therefore, resistance of the given expression is 8.89 ohm.

Buddy I am not sure if this is what you wanted

If anything else I could help you with I would be happy to

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