A wire of resistance R and length L is compressed to one third of it's original length. New resistance of wire is
Answers
Answered by
0
Answer:
Taking Volume Constant...
A - Cross section area of wire (πr^2)
L- Length of wire.
A2.L2 = A1.L1
r2 = 2.r1 ( As diameter is doubled)
A2= 4.A1
This gives.... L2 = L1/4
If radius ( diameter) is doubled length becomes one fourth.
Resistance is proportional to L/A.
R2 =R1/16.
Similar questions