Question

a wire of resistance r and resistivity p is doubled on it such that the length is halved and area of cross section is doubled. find i) its new resistance and ii) its new resistivity. (temperature remains the same(iii
the circular wire. ​

Answer 1

Answer:Let original length= l

and area  = A

now, R=  ρl/A

if new length becomes  $\frac{l}{2}$  , new area =2A

now, R1= ρ($\frac{l}{2}$) / 2A

R1= $\frac{1}{4}$ (ρL/A)

R1=$\frac{1}{4}$(R)

And resistivity remains the same

and if the wire is turned into circle then resistance and resistivity remains the same

HOPE IT HELPS YOU....!!!

Answer 2

Explanation:

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