Question

a wire of resistance R is cut into 3 equal parts
1. find the value of resistance of each part in terms of the original resistance R.
2. if these 3 pieces are connected in parallel . what is the ratio of the resistance so obtained with the original resistance.

plz give the complete method

Answer 1

Hey! ! !

Solution :-

☆ R [ohm] = r [Ohm*m] * L [m] / S [mm2]

Where R: resistance

r: resistivity

L: length

S: section

So..

R = k * L

And you split 3 equal parts, L1 = L/3

So R1 = k *L/3

R // = R1 / 3

R// = k*L /9

You know R = k*L ( it's your cable before cut)

R// = R/9

Where

R: resistance before cut into 3 equal pieces

R//: Resistance of 3 peaces in parallel


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☆ Regards :- ♡♡《 Nitish kr singh 》♡♡

Answer 2

1. = R' / 3. ( R ' is the original resistsnce)

2. The ratio of equivalent resistance with originsl resistance =

1 / R ' = 3/R +3/R+3/R

1/R ' = 9/R

R/ R ' = 9 : 1

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