Question

a wire of resistance r is cut into 3 equal parts. of these equal parts are connected in parallel, find the resistance of the combination

Answer 1

Answer:

Explanation:when the wire is divided into equal parts it results to r/3 each

So 1/R=1/(r/3)+1/(r/3)+1/(r/3)

1/R=3/r+3/r+3/r

1/R= 9/r

R=r/9

Answer 2

Answer: The resistance of the combination is r/9

Explanation

A wire of resistance 'r' is cut into 3 equal parts.

Therefore, 3 equal resistance new wires are formed

Imagine them as resistors ( each resistor has resistance r/3 because each resistor has 1/3 the total resistance before the wire was cut)

They are connected in parallel

Therefore, Use resistors in parallel formula

1/Rp = 1/R1 + 1/R2+ 1/R3

1/Rp =  3/r + 3/r + 3/r

1/Rp =     9/r

 Rp =  r/9

Hope this helps!!