Question

A wire of resistance R is cut into 4 equal parts. These 4 parts are now connected in parallel. Find the ratio of effective resistance of this combination to the original resistance.​

Please help guys its quite urgent

Answer 1

Answer:

R/16 .

Explanation:

We know that Resistance is proportional to length. Therefore when a wire will be cut into 4 equal halves , the resistance of each part will be ,

$\rm\implies Resistance_{each \ part }=\dfrac{R}{4}$

And then these are connected in parallel. We know that if n resistors are connected in parallel then , the effective resistance will be ,

$\rm\implies R_{net}=\dfrac{R}{n}$

Substituting respective values ,

$\rm\implies R_{net}= \dfrac{ \dfrac{ R} {4}}{4} \\\\\rm\implies R_{net}=\dfrac{ R}{4\times 4 }\\\\\rm\implies \boxed{\red{\rm R_{net}=\dfrac{R}{16}}}$

Answer 2

Answer:

here izz ur answer

(≡^∇^≡)

A piece of wire of resistance r is cut into 4 equal parts. So, each of this part will have resistance equal to r / 4. There are four parts of cut wire each with resistance equal to r / 4. Hence, the equivalent resistance of the combination when connected in parallel is r / 16.