Question

. A wire of resistance 'R' is cut into four equal
parts and they are bundled together side by
side to form a thicker wire. The resistance of
the bundle is (CPMT 91)
​

Answer 1

Answer:

R/16

Explanation:

A wire of resistance 'R' is cut into four equal

parts and they are bundled together side by

side to form a thicker wire. The resistance of

the bundle is R/16

Answer 2

Answer:

ρL/16A (or) R/16

Explanation:

To solve this, you must clear your fundamentals of 'Resistance'.

A simple formula ρl/A is enough to solve this question.

R = ρL/A

Where:

R - Resistance of the wire

ρ - Resistivity [This remains constant on the material]

L - Length of wire

A - Area of the cross section of the wire

In this question:

Initially L = L, finally L = L/4

'A' and ρ will remain constant.

But then, the wires are bundled together. So, area of cross section will become 4A, L = L/4, ρ remains constant.

R = ρ(L/4)/(4A) = ρL/16A

ρL/16A is the final resistance, so final resistance will be R/16, where R is the initial resistance.

Hope it helps!