Question

a wire of resistance R is cut into n equal parts. These parts are then connected in parallel. the equivalent resistance of com bination will be
a, nR
b, R/n
c, n/R
d, R/n^2

Answer 1

the wire is cut into n equal parts...

so the resistance of each part= R/n

these parts are then connected in parallel....

resistance of the combination will be..

n + n + n + ........n times = 1

R R R R(equi.)

i.e.,

n × n => n^2/R = 1

R R(equi.)

hence, total resistance=R/n^2....