A wire of resistance R is stretched to twice of its original length and area decrease to half of its original value.its new resistance will be. a)4R b)R/9. c)3R. d)R/3
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Answer:
R=
A
pL
On, stretching a wire (a) volume of wire remains constant
(b) length of wire increases
(c) Area of cross section decreases
(d) Resistivity of wire = constant
On doubling length by stretching :
L
1
=2L
A
1
=A/2
∴R
1
=
A
1
pL
1
=
2
A
p(2L)
=
A
4pL
=4r
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