a wire of resistant 20 ohms is bent to form a closed square what is the resistance across a diagonal of the square
Answers
Explanation:
When it is bent into a square, each side of the square will get 5 Ω resistance.
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12th
Physics
Current Electricity
Electrical Resistance & Resistivity
A wire of resistance 20Ω is...
PHYSICS
A wire of resistance 20Ω is bent to form a closed square. What is the resistance across a diagonal of the square.
December 26, 2019
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Sparjan Gautam
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ANSWER
If the wire is bent to form a square, then the resistance of the side of the square =
4
20
=5Ω
Across the diagonal, first calculate resistance through the two sides i.e. R
1
=5+5=10Ω
then through the diagonal,
R
2
=
(5
2
+5
2
)
=5×
2
As R
1
and R
2
are paralell to each other
R
1
=
R
1
1
+
R
2
1
R
1
=
10
1
+
5×
2
1
R
1
=
10×
2
(
2
+
2
)
R
1
=
10×
2
2×
2
R
1
=
10
2
R
1
=
5
1
R=5Ω
Answer:
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Explanation:
the wire is bent to form a square, then the resistance of the side of the square =
4
20
=5Ω
Across the diagonal, first calculate resistance through the two sides i.e. R
1
=5+5=10Ω
then through the diagonal,
R
2
=
(5
2
+5
2
)
=5×
2
As R
1
and R
2
are paralell to each other
R
1
=
R
1
1
+
R
2
1
R
1
=
10
1
+
5×
2
1
R
1
=
10×
2
(
2
+
2
)
R
1
=
10×
2
2×
2
R
1
=
10
2
R
1
=
5
1
R=5Ω