A wire of resistivity is stretched to double of its length. Find its new resistance
and resistivity.
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Given Resistance of a wire
R= pL/a
On, stretching a wire (a) volume of wire remains constant
(b) length of wire increases
(c) Area of cross section decreases
(d) Resistivity of wire = constant
On doubling length by stretching :
L 1 =2L
A 1 =A/2
∴R 1 = A 1
pL 1 = 2A
p(2L)= A4pL
=4R
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