A wire of uniform cross section having resistance 8 0 is bent to form a square ABCD. End A is connected to a point P on the side DC by a wire AP of resistance 1 Q. When V potential difference is applied between A and C, the resistance of part DP if the points B and P are to be at same potential
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given = A wire of uniform cross section having resistance 8 0 is bent to form a square ABCD.
to find = effective resistance
solution=
let the effective resistance will be XΩwhich is between CP points so , (1-x)
AP= effective resistance .....( points B and P will be equipotential )
CP= effective resistance .....( points B and P will be equipotential )
AP=CP
i.e. = (1 +X)X1 / (1 + X)+1= (1-X)
total resistnce 8Ω .......(given in question)
AB = BC = CD = AD = 2Ω
(1 +X) = (1-X) X (2+X)
1+X = 2+X-2X X2
X²+2X-1= 0
X= (√2-1)
the effective resistance is X= (√2-1)
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