Question

a wire placed along east west direction carries a current of 10 ampere from west to east direction determine the magnetic field due to a 1.8 CM piece of wire at a point 300 CM North East from the peace​

Answer 1

Given that,

Current = 10 A

Length = 1.8 cm

Distance = 300 cm

The magnetic field due to 1.8 cm piece of wire at a point 300 CM North East from the piece​.

So, The angle will be  45°

We need to calculate the magnetic field

Using bio savart law

$dB=\dfrac{\mu}{4\pi}\times\dfrac{idl\sin\theta}{r^2}$

Where, i = current

dl = length of pices

r = distance

Put the value into the formula

$dB=\dfrac{10^{-7}\times10\times1.8\times10^{-2}\sin45}{300\times10^{-2}}$

$dB=5.10\times10^{-9}\ T$

Hence, The magnetic field will be $5.10\times10^{-9}\ T$

Answer 2

Answer: 1.4*10^-9 T

Explanation: