A wire resistance 20 ohm is bent in the form of a closed circle. what is effective resistance between two points at the ends os any diamter of the circle
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hii mate !!
Resistance given here is 20 ohm
As it is bend into wire so, L = 2πr
so, Ri = Rho×2πr/A = 20 ohm
Now, resistance between two point at the end of diameter can be given by
1/R = (1/Ri/2)+(1/Ri/2) {as half of the wire is attached to the other half so it may be considered as parallel connection}
1/R = 1/10+1/10 { Ri = 20ohm so Ri/2 = 10 ohm }
or 1/R = 2/10
so, R = 5 ohm ,(across ends of diameter)
hope it helps !!☺☺☺☺☺
Resistance given here is 20 ohm
As it is bend into wire so, L = 2πr
so, Ri = Rho×2πr/A = 20 ohm
Now, resistance between two point at the end of diameter can be given by
1/R = (1/Ri/2)+(1/Ri/2) {as half of the wire is attached to the other half so it may be considered as parallel connection}
1/R = 1/10+1/10 { Ri = 20ohm so Ri/2 = 10 ohm }
or 1/R = 2/10
so, R = 5 ohm ,(across ends of diameter)
hope it helps !!☺☺☺☺☺
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