Question

A wire square area =121 cm square find area bent to circle

Answer 1

Here we go!
$area \: of \: square = 121 \: sq \: cm \\ length \: of \: side \: of \: square = \sqrt{121} = 11 \\ perimeter \: of \: square = 4 \times 11 = 44 \\ now \: the \: perimeter \: of \: square = cirumference \: of \: circle \\ therefore \: \\2 \pi {r} = 44 \\ r \: is \: the \: radius \: of \: circle \: \\ = > \frac{2 \times 22}{7} \times {r} = 44 \\ = > {r} = 44 \times \frac{7}{44} \\ = > r = 7$
Therefore the required radius is 7 cm
now the area of the circle= 22/7*7^2
= 22*49/7
=22*7
=154
The required answer is 154 Sq. Cm

Answer 2

Heya user ,
Here is your answer !!

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Area of the square = 121 cm² .

There fore ,
side of the square = √121 cm = 11 cm .

So , the perimeter of the square = 11 * 4 cm = 44 cm .

The circle was made from this wire too .
So , the perimeter of the square will be equal to the circumference of the circle , i.e., it is equal to 44 cm .

Now , the formula to calculate the circumference of a circle is = 2πr .

So , acc . to the equation , we get ,
2πr = 44 
=>  πr = 22 
=> 22 / 7 * r = 22
=> r = 7 cm .

Now , area bounded by the circle is ----->
= πr²
= 22 / 7 * 7 * 7 cm²
= 154 cm² . { Answer } 

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Hope it helps !!