Question

a wire stretched between two rigid supports vibrates in its fundamental mode​

Answer 1

Answer:

given,

mass of wire, m = 3.5 × 10^-2 kg

linear mass density , u = 4 × 10^-2 kg

so, length of wire , l = m/u = 3.5/4 = 0.875m

frequency of fundamental mode , f = 45Hz

for wire stretched between two rigid supports,

fundamental mode is given by,

l = λ/2 => λ = 2l = 2 × 0.875 = 1.75 m

now, use formula, v = λf , to find speed of wave

so, v = 1.75 × 45 = 78.75 m/s

now, use formula , $v^2u$

= (78.75)² × 4 × 10^-2

= 248.06N

Explanation: