a wire under tension vibrates with a frequency of 450 hertz what would be the fundamental frequency if the wire were half as long twice as thick and under one-fourth tention:
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Answer:
159.12 Hz
Explanation:
As per the question,
Given data:
A wire under tension vibrates with a frequency = 450 hertz
According to the speed of the string, we have
Let V₁ = 450 Hz
Now,
The wire were half as long twice as thick and under one-fourth tention:
New length = l/4
m = 2m
And
Divide V₂ by V₁, we get
∴ v₂ = 159.12 Hz
Hence, the fundamental frequency = 159.12 Hz
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