Physics, asked by meghna17, 1 year ago

a wire under tension vibrates with a frequency of 450 hertz what would be the fundamental frequency if the wire were half as long twice as thick and under one-fourth tention:

Answers

Answered by Eshita111
4
please verify the answer and let me know !!!
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Answered by sushilachoubay758
2

Answer:

159.12 Hz

Explanation:

As per the question,

Given data:

A wire under tension vibrates with a frequency = 450 hertz

According to the speed of the string, we have

v=\sqrt{\frac{T\cdot l}{m}}

Let V₁ = 450 Hz

Now,

The wire were half as long twice as thick and under one-fourth tention:

New length = l/4

m = 2m

V_{1}=\sqrt{\frac{T\cdot l}{m}}

And

V_{2}=\sqrt{\frac{T\cdot l}{2m\cdot 4}}

Divide V₂ by V₁, we get

\frac{V_{2}}{V_{1}}=\frac{1}{\sqrt{8}}\\V_{2}=\frac{450}{\sqrt{8}}

∴ v₂ = 159.12 Hz

Hence, the fundamental frequency = 159.12 Hz

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