Math, asked by ridisha75, 10 months ago

A wire was bent to form a square of side 21cm. The same wire was then straightened and rebent to form a regular square hexagon. Find the length of each side of the hexagon.​

Answers

Answered by gugan64
17

Answer:

Given:-

Number of sides in hexagon : 6

Perimeter of regular hexagon : 21

To find:-

the value of one side

Solution:-

X+X+X+X+X+X = 21

=> 6X  =  21

X  =  21/6

X  =  7/2

X  = 3.5 CM

Step-by-step explanation:

Answered by Anonymous
6

\bigstar EXPLANATION \bigstar

  • Question

A wire was bent to form a square of side 21cm. The same wire was then straightened and rebent to form a regular square hexagon. Find the length of each side of the hexagon?

  • Procedure

As the same wire is first bent into a square and then again into a hexagon

That means the length of wire didn't change

Therefore,

The perimeter of the two figures made are equal

Side of the square made using the wire = 21 cm

We know that,

The Perimeter of the square = 4 * (Length\:of\:the\:side)

Perimeter of the square made using the wire = 4 * 21 = 84 cm

We know that,

The perimeter of the regular hexagon = 6 *(Length\:of\:side)

Let the length of each of the regular hexagon be x

Perimeter of the regular hexagon made using the wire = 6x

As the perimeter of both the figures are same

Therefore,

84 = 6x

x = \frac{84}{6}

x = 14

  • Extra-Information

i) Perimeter of triangle = Sum of all the sides

ii) Area of triangle = \frac{bh}{2}

iii) Area of triangle = \sqrt{s(s-a)(s-b)(s-c)}

where s = \frac{(a+b+c)}{2} and a, b,c are the sides of the triangle

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