A wire when bend in the form of an equilateral triangle encloses an area 121root3 cmsquare. if the square wire is bent into the form of a circle. Find the area of the circle. (use pie=3.14)
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Area of an equilateral triangle=√3×side/4 121√3 = √3×s/4
121√3×4/√3 = s
484 = s
s = 484 cm = circumference of circle
C = 484
2πr = 484
r = 484/2π = 77.07 cm
Area of circle = πr^2 = 3.14 × 5939.8 ~ 18605.32 cm.sq.
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