Question

A wire when bent in the form of a square enclosed an area of 992.25cm square.If the same wire is bent to form a semi-circle,what would be the radius of the semi circle

Answer 1

Step-by-step explanation:

Area Of square a^2 = 81 ====> a = 9

The wire when bent in a form of Square i.e. the total perimeter of the square

Therefore,Perimeter of Square = 4a = 4*9 = 36 which is total length of the wire

the wire which is bent in the form of semicircle forms circumference of semicircle

therefore circumference is 22/7r+2r = 36 where 'r' is radius

(22+14)*r/7 = 36

r = 7 cm

Therefore area of semicircle is {(22/7)r^2}/2 = (1/2)*(22/7)*7*7

By simplifying

we get Area of semicircle = 77 cm^2

hope it's helpful