Question

A wire when bent in the form of a square encloses an area of
625 m2.Find the largest area enclosed by the same wire when bent to form a rectangle of breadth 22m.

Answer 1

616m^2
Explanation:
Let the length of the wire be l
And let the side of the square formed be a
A^2=625m2
a= sqrt(625)
a=25m
Total perimeter of the square formed= Length of wire
4a=l
4*25=l
100m=l

Now when the same wire is bent to form a rectangle of breadth 22m,
Perimeter of rectangle=Length of wire
2(length+22)=100
2l+44=100
2l=100-44
2l=56
l=56/2
l=28m

Hence area of the rectangle so formed= Length*Breadth
Area=22*28
Area=616m^2

Answer 2

Answer:

616m^2

Explanation:

Let the length of the wire be l

And let the side of the square formed be a

A^2=625m2

a= sqrt(625)

a=25m

Total perimeter of the square formed= Length of wire

4a=l

4*25=l

100m=l

Now when the same wire is bent to form a rectangle of breadth 22m,

Perimeter of rectangle=Length of wire

2(length+22)=100

2l+44=100

2l=100-44

2l=56

l=56/2

l=28m

Hence area of the rectangle so formed= Length*Breadth

Area=22*28

Area=616m^2