A wire when bent in the form of a square encloses an area of 576 m^2. Find the largest area enclosed by the same wire when bent to
form equilateral triangle. ( square root of 3 = 1.732)
i. 443 39 m^2
ii. 375 m^2
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Given, a wire when bent in the form of a square encloses an area of 576 sq.m .
Area of Square=(side) 2
576=(side) 2
side= _/576 =24 cm
Perimeter of square =4×side
=4×24
=96 cm.
When same wire is formed into equilateral triangle, then perimeter of square is equals to perimeter of triangle.
∴ Perimeter of equilateral triangle =96 cm
or, 3×side=96 cm
side= 3/96 =32 cm.
=256 _/3cm 2
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