Question

A wire when bent in the form of a square
encloses an area of 484 m². Find the largest
area enclosed by the same wire when bent to
form:
(i) an equilateral triangle.
(ii) a rectangle of breadth 16m. Please☠no spam☠​
​

Answer 1

Area (when it is square)

a² = 484m²

a = √484 m²

length of wire = 4a = 4 × 22 = 88m

(i)Equilateral triangle (Image 1):-

3P = length of wire = 88m

P = 88/3 m

☆area = √3/4 p² = √3/4 × (88/3)²

= 1936√3/9 m²

(ii)Rectangle of breadth 16m ( Image 2):-

2( l + b) = 88

=> ( l + b) = 44

=> l = 44 - 16

=> l = 28 m

☆area = l × b = 28 × 16

= 448 m²

___________________________________

hence,

》Area of equilateral triangle = 1936√3/9 m²

》Area of rectangle = 448 m²

Answer 2

Answer:

Your answer is in the ATTACHMENT...