A wire when bent in the form of an equilateral triangle encloses an area of 36√3 cm²,
Find the area enclosed by the same wire when bent to form:
(i) a square, and
(ii) a rectangle whose length is 2 cm more than its width.
Answers
Answered by
7
Answer:
area = 6x3 = 18
area of triangle = 1/2 x base x height
18 x 2 = base x height
36 = base x height
base = 36 x height
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Answered by
8
Step-by-step explanation:
side of the triangle =12cm
perimeter =36m
i)perimeter of square=4a=36
a=9,area=a²=81
ii)2(L+L-2)=36
L=10,W=8
area=8×10=80
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