Question

A wire when bent in the form of an equilateral triangle encloses an area of 36 13 cm?
Find the area enclosed by the same wire when bent to form.
(1) a square, and
(ii) a rectangle whose length is 2 cm more than its width.​

Answer 1

$\boxed{\sf{Total\: Length\: of \:Wire = 3\times Side = 3\times 12\:cm = 36\:cm}}$

$\boxed{\longrightarrow\sf{Area\:of\:Square=Side\times Side = 9\:cm\times 9\:cm= 81\:cm^2}}$

$\boxed{\longrightarrow\sf{Area\:of\:Rectangle=Length\times Breadth = 10\:cm\times 8\:cm = 80\:cm}}$