Question

A wire when bent in the form of square, encloses an area of 146.41 cm*cm . If this wire is straightened and then bent to form a circle, what will be the area of the circle so formed?

Answer 1

Answer:

186.34 cm²

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Step-by-step explanation:

Area of square = Side²

Side² = 146.1  cm²

Side = 12.1 cm

Perimeter = 4*12.1 = 48.4

Perimeter of circle = 2 * Pie * R = 48.4

2 * (22/7) * R = 48.4

R = 48.4 * 7 / 44

R = 7.7 cm

Area = Pie * R²  =  (22/7) * (7.7)²

= 22 * 7.7 * 1.1

= 186.34 cm²

Answer 2

Answer:

Area of Square = Side² = 146.41

Side = √146.41 = 12.1 cm

Length of wire = Perimeter of Square = 4 x 12.1 = 48.4 cm

Circumference of circle = length of wire => 2πr = 48.4

r = 48.4 x 7 / 2 x 22 = 338.8 / 44 7.7 cm

Area of circle = πr² = 22 x 7.7 x 7.7 / 7 =186.34 cm²

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