Question

A wire which is bent in the shape of a square of area 49 cm’is rebent to form a rectangle of breadth
4 cm. Find the area of rectangle formed on rebending the wire. Also, find which shape occupies more
area and by how much.​

Answer 1

Given,

Area of sq. 49

side=√49

=7cm

perimeter=28cm

perimeter of sq.=per. of rec.

28=2(4+l)

28=8+2l

l=10

area of rec. lb

10×4

40cm2

AREA IS MORE OCCUPIED BY SQUARE

Answer 2

Step-by-step explanation:

area of square =s^2=49

side of the square = s = 7cm

perimeter of the square is 4s = 4×7=28cm

perimeter of rectangle is also 28cm

2(l+b)=28cm

2(l+4)=28cm

l= 10cm

area of rectangle is l×b= 10×4= 40cm2

sqaure occupies more area than rectangle by 9cm2