Question

A wire which is bent in the shape of a square of perimeter of area 49 cm² is regent to form a rectangle of breadth 4 cm. Find the area of rectangle formed on rebending the wire. Also, find which shape occupies more area and by how much.​

Answer 1

Answer:

Step-by Side of square =8 cm

Perimeter of square =32 m

Length of rectangle =10 cm

Therefore,

2(l+b)=32

10+b=16

b=6

Therefore, breadth = 6m

Now, area of square = side×side=8×8=64 cm  

2

 

Area of rectangle = length×breadth=10×6=60 cm  

2

 

Answer 2

Step-by-step explanation:

side of square=8cm

perimeter of square =32m

length of rectangle=10cm

Therefore 2(l+b)=32

10+b=16

b=6

Area of square=s×s=8×8=64cmsquare

area of rectangle=(l×b)=10×6=60cm square

there square encloes more area